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Added momentum and finished the classical mechanics section for now.

This commit is contained in:
Luc Bijl 2024-08-17 21:48:40 +02:00
parent 3a4f13d677
commit 79c0ba6edb
5 changed files with 32 additions and 8 deletions

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- 'Lagrangian formalism': physics/classical-mechanics/lagrangian-mechanics/lagrangian-formalism.md
- 'Lagrange equations': physics/classical-mechanics/lagrangian-mechanics/lagrange-equations.md
- 'Lagrange generalizations': physics/classical-mechanics/lagrangian-mechanics/lagrange-generalizations.md
- 'Applications':
- 'Celestial mechanics': physics/classical-mechanics/lagrangian-mechanics/applications/celestial-mechanics.md
- 'Oscillations': physics/classical-mechanics/lagrangian-mechanics/applications/oscillations.md
- 'Hamiltonian mechanics':
- 'Hamiltonian formalism': physics/classical-mechanics/hamiltonian-mechanics/hamiltonian-formalism.md
- 'Equations of Hamilton': physics/classical-mechanics/hamiltonian-mechanics/equations-of-hamilton.md
@ -187,7 +184,7 @@ nav:
- 'Kerr geometry': physics/relativistic-mechanics/kerr-geometry.md
- 'Wave geometry': physics/relativistic-mechanics/wave-geometry.md
# - 'Quantum mechanics':
# - 'Statistical mechanics'
# - 'Statistical mechanics':
- 'Electromagnetism':
# - 'Electrostatics':
# - 'Magnetostatics':

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site_name: Mijn aantekeningen
site_name: Wiskunde en natuurkunde wiki
docs_dir: '../../docs/nl'
theme:

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# Momentum
> *Definition 1*: the **momentum** $\mathbf{p}$ of a particle is defined as the product of the mass and velocity of the particle
>
> $$
> \mathbf{p} = m \mathbf{v},
> $$
>
> with $m$ the mass of the particle and $\mathbf{v}$ the velocity of the particle.
For the case that $\mathbf{v}: t \to \mathbf{v}(t) \implies \mathbf{v}'(t) = \mathbf{a}(t)$ we have the following theorem.
> *Theorem 1*: let $\mathbf{v}$, $\mathbf{a}$ be the velocity and acceleration of a particle respectively, if we have
>
> $$
> \mathbf{v}: t \to \mathbf{v}(t) \implies \forall t \in \mathbb{R}: \mathbf{v}'(t) = \mathbf{a}(t),
> $$
>
> then
>
> $$
> \mathbf{p}'(t) = \mathbf{F}(t),
> $$
>
> for all $t \in \mathbb{R}$.
??? note "*Proof*:"
Will be added later.